The equation of line wx is 2x+y=-5. what is the equation of a line perpendicular to line wx in slope-intercept form that contains point (-1,-2)?

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + y = - 5 into this form by subtracting 2x from both sides

y = - 2x - 5 ← in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - , hence

y = x + c ← is the partial equation of the perpendicular line

To find c substitute (- 1, - 2) into the partial equation

- 2 = - + c ⇒ c = -

y = x - ← equation in slope- intercept form

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

step-by-step explanation:

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