Does anyone know how to do
a store is having a sale on chocolate chips and walnuts. for 3 pounds of chocolate chips and 2 pounds of walnuts, the total cost is $13. for 8 pounds of chocolate chips and 4 pounds of walnuts, the total cost is $33. find the cost for each pound of chocolate chips and each pound of walnuts.
cost of each pound of chocolate chips: $
cost for each pound of walnuts: $

Cost of a pound of chocolate chips: $3.5

Cost of a pound of walnuts: $1.25

Step-by-step explanation:

x - cost of a pound of chocolate chips

y - cost of a pound of walnuts

We create two equations based on the information we have:

3x+2y=13

8x+4y=33

The whole point of these problems os to get rid of x or y. In this question, we can do this by multiplying both sides of the first equation by 2, and then subtracting it from the second equation:

8x+4y=33

6x+4y=26

2x=7

x=3.5

Then we change x for 3.5 in the first equation:

3×3.5+2y=13

10.5+2y=13

2y=2.5

y=1.25

Hope this helps!

a. is correct

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺