Arectangle has a length 10 m less than twice its width. when 2 m are added to the width, the resulting figure is a square with an area of 196 m squared. find the dimensions of the original rectangle.

The length of the original rectangle is 14 meters and the width of the original rectangle is 12 meters

Step-by-step explanation:

Let

l ----> the length of the original rectangle

w ----> the width of the original rectangle

we know that

----> equation A

----> area of a square

Solve for w

square root both sides

-----> this solution not make sense

so

Find the value of L

therefore

The length of the original rectangle is 14 meters and the width is 12 meters

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation