Can anyone me with this pre calc question?

y=4x-4

Step-by-step explanation:

The equation of a line is slope-intercept form is: y=mx+b where m is the slope and b is the y-intercept. This is the required form I think. Your document says write in slope... can't read the rest because it is cut off.

I'm actually going to use point-slope form which is: y-y1=m(x-x1) where m is the slope and (x1,y1) is a point we know that is on the line.

We have m=4.

We can actually find a point on the line. Both the line and the curve y=x^2 cross at x=2.

So we find the corresponding y-coordinate on our line to x=2 by plugging into x^2.

x^2 evaluated at x=2 gives us 2^2=4.

So we have the slope m=4 and a point (x1,y1)=(2,4) on the line.

Let's plug it into the point-slope form:

y-4=4(x-2)

Now the goal was y=mx+b form so let's solve our for y.

y-4=4(x-2)

Distribute 4 to terms in ( ):

y-4=4x-8

Add 4 on both sidea:

y=4x-4

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

parallel and congruent

step-by-step explanation:

the movement of translation is linear.   these have the same translation because you are using the same rule for each point of the triangle so you will see the same slope being used to get from a point on the triangle to its image.

same slope!   you should think parallel when you see those 2 word together (well unless it's the same line but it can't be because we are coming from different points here)

congruent! because each point is being moved the same distance.