The length of country and western songs is normally distributed and has a mean of 170 seconds and a standard deviation of 40 seconds. find the probability that a random selection of 16 songs will have mean length of 158.30 seconds or less. assume the distribution of the lengths of the songs is normal.

0.1210

Step-by-step explanation:

Given : The length of country and western songs is normally distributed with

Sample size :

Let x be the length of randomly selected country song.

z-score :

The probability that a random selection of 16 songs will have mean length of 158.30 seconds or less by using the standard normal distribution table will be

=

Hence, the probability that a random selection of 16 songs will have mean length of 158.30 seconds or less is 0.1210

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: