Agambler mixed a "cheat" die with all sixes into a box of eight normal dice. she chooses one at random, rolls it twice, and gets six both times. what is the probability that she chose the "cheat" die?

The probability is

Step-by-step explanation:

There are a total of 9 die in the box after she added the "cheat" die. Since there is only 1 "cheat" die in the box and chooses a die at random then the probability of her having chosen the cheat die is . The fact that she rolled two sixes did not affect when she choose the die therefore the probability remains as .

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(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3