Acylinder has a height of 16cm and a radius of 5cm. a cone has a height of 12cm and a radius of 4cm. if the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (use 3.14 as an approximation of ‘pi’.)
radius of cylinder = 5cm
radius of cone = 4cm

1055.04

Step-by-step explanation:

Cylinder

h = 16 cm

r = 5 cm

Volume = ?

Formula

V=pi * r^2 * h

Solution

V = pi r^2*h

V = 3.14 * 5*5*16

V = 1256 cm^3

Cone

h = 12 cm

r = 4 cm

Formula

V = (1/3) pi r * r * h

Solution

V = (1/3) 3.14 * 4 * 4 * 12

V = (1/3) 602.88

V = 200.96

Answer

Volume of unoccupied region = Cylinder - Cone

Volume of unoccupied region = 1256 - 200.96

Volume of unoccupied region = 1055.04

You will have to round it to the number of digits required.

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.