Acomputer purchased for $1,050 loses 19% of its value every year.
the computer's value can be modeled by the function v(t)=a⋅b^t, where v is the dollar value and t the number of years since purchase.
(a) in the exponential model a= and b= .
(b) in how many years will the computer be worth half its original value? round answer to 1 decimal place.
the answer years

A) a = 1050 and b = 0.81

B) 3.3

Step-by-step explanation:

Original price of the computer = $ 1050

Rate of decrease in price = r = 19%

This means, every year the price of the computer will be 19% lesser than the previous year. In other words we can say that after a year, the price of the computer will be 81% of the price of the previous year.

Part A)

The exponential model is:

Here, a indicates the original price of the computer i.e. the price at time t = 0. So for the given case the value of a will be 1050

b represents the multiplicative rate of change i.e. the percentage that would be multiplied to the price of previous year to get the new price. For this case b would be 81% or 0.81

So, a = 1050 and b = 0.81

The exponential model would be:

Part B)

We have to find after how many years, the worth of the computer will be reduced to half. This means we have the value of v which is 1050/2 = $ 525

Using the exponential model, we get:

Taking log of both sides:

Thus, after 3.3 years the worth of computer will be half of its original price.

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: