Yvaries inversely with x. when y = 9.6, x = 12. what is the value of k, the constant of inverse variation?
round to the nearest tenth, if necessary.
-y varies inversely with x, and k (the constant of variation) = 5.6. what is the value of y when x = 4?
round to the nearest tenth, if necessary

Question 1:

For this case we have an equation of the form:

Where,

Then, substituting values we have:

From here, we clear the value of k.

We have then:

the constant of inverse variation is:

Question 2:

For this case we have:

Where,

Then, substituting the value of the constant we have:

We now substitute the value of x:

 the value of y when x = 4 is:

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )