The mayor is interested in finding a 95% confidence interval for the mean number of pounds of trash per person per week that is generated in city. the study included 120 residents whose mean number of pounds of trash generated per person per week was 31.5 pounds and the standard deviation was 7.8 pounds. what is the confidence interval for the mean number of lbs of trash per person per week that is generated in the city?

(30.09, 32.91)

Step-by-step explanation:

Mean number of pounds of trash = x = 31.5 pounds

Standard deviation = s = 7.8 pounds

Sample size = n = 120

Confidence level = 95%

Since, we are given the sample standard deviation instead of the population standard deviation, we will use t-test to find the confidence interval.

Degrees of freedom = df = n - 1 = 120 - 1 = 119

The t-value associated with 95% confidence interval and df=119 from the t-table comes out to be:

t = 1.98

The formula to calculate the confidence interval is:

Using the values in above expression we get:

Thus, the 95% confidence interval for the mean number of lbs of trash per person per week that is generated in the city is (30.09, 32.91)

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

mark brainliest