Which of the following would be the most logical first step to solving this
quadratic equation?
2x2-x+ 2 = -11
o
a. divide both sides by x.
o
b. take the square root of both sides.
o
c. set up smaller equations using the zero product rule.
o
d. add 11 to both sides.

D is correct option

Step-by-step explanation:

The correct option is D.

The standard quadratic equation is ax²+bx+c=0

Where a and b are coefficients and c is constant.

It means that constant are on the L.H.S and there is 0 on the right hand side.

Therefore to make it a quadratic equation first of all you have to add 11 at both sides so that the R.H.S becomes 0.

The given equation is:

2x2-x+ 2 = -11

If we add 11 on both sides the equation will be:

2x2-x+ 2 +11= -11+11

2x^2-x+13=0

Thus the correct option is D

You can further solve it by applying quadratic formula

answer is:

1.75 pounds

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2