You go car shopping, knowing that you can afford monthly payments of $400. you also have a trade-in that you know is worth $3000. you intend to take a loan at an interest rate of 5% compounded monthly. if the payments last for 4 years, what is the most expensive car you can afford? round your price to the nearest whole dollar.

  $20,369

Step-by-step explanation:

The annuity formula can tell you the present value P of a monthly payment A made n time at interest rate r per payment period.

  P = A(1 -(1+r)^-n)/r

Here, we have A = 400, r = .05/12, n = 12*4 = 48, so the loan amount can be ...

  P = 400(1 -(1+.05/12)^-48)/(.05/12) ≈ 17,369.18

Adding the value of the trade-in, we find we can afford a car priced at ...

  $3000 + 17,369 = $20,369

ok

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°