How many solutions are there to the equation x1 +x2 +x3 +x4 +x5 = 18, where x1, x2, x3, x4, x5 are non-negative integers, given the follow restrictions: four of the variables must be odd, and the remaining variable (which may be odd or even) yield a remainder of 2 when divided by 3? justify your answer.

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to find the perimeter, you add up all the lengths of the sides. in this case you would have to add up 18+22+40+80 which equals 160.

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could