Mathematics, 19.07.2019 03:10 funmi5504

Brandon has a fish tank that can hold 38 gallons of water.
- on monday (1st day of the month) there were 38 gallons of water in the tank.
- the fish tank loses 0.75 gallons of water on every odd numbered day.
- brandon adds 0.5 gallons of water to the fish tank on days that are multiples of 3
- how much total water will brandon need to add on the last day of the month (31 days in this month) to fill the tank to 38 gallons
- show 2 different ways to solve this problem

Answers: 1

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Answers

Answer from: Fionaauggies

7 gallons

Step-by-step explanation:

The first method

You will start with 38 gallons of water on 1st day then as you count the days, subtract 0.75 gallons of water in every odd number day, and add 0.5 gallons of water for everyday that is a multiple of 3 up to the 31st day.Then find the difference of the value you get with the initial amount of water that the tank could hold.

The second method

Given 0.75 gallons of water are lost in every odd numbered day and 0.5 gallons of water are added in every day that is a multiple of 3 then;

⇒ identify all days that are odd in this month.

They are 16 days

⇒Find the amount of water that will be lost in 16 odd number days of that month

16×0.75=12 gallons

⇒Find the number of days that are multiple of 3

They are 10 days

⇒Find amount of water that can be added in 10 days

10×0.5=5 gallons

⇒The water that will be in tank on 31st will be

38-12+5

(38+5)-12

43-12=31 gallons

⇒Amount of water to add

38-31=7gallons

Answer from: Quest

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Answer from: Quest

idk

step-by-step explanation:

i don't know

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Brandon has a fish tank that can hold 38 gallons of water.
- on monday (1st day of the month)...