What is the equation of the line that passes through (-3, -1) and has a slope of 2,5 ? put your answer in slope-intercept form.

y+1 = 2/5(x+3)

Step-by-step explanation:

We have a point and a slope so we can use point slope form

y-y1 = m(x-x1) where m is the slope and (x1,y1) is the point

y--1 = 2/5 (x--3)

y+1 = 2/5(x+3)

step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2