If you decrease the distance between two celestial objects by a factor of 2.5, how does the resultant gravitational force between the two objects compare to the original force? the force is times stronger.
only enter your numerical answer below 0 do not include units. report your answer to 2 decimal places.

 The force is 6.25 times stronger.

Step-by-step explanation:

The formula to find the force of attraction between any two object is given by :-

                                (i)

, where M and m are the masses of the objects , d is the distance between them and G is gravitational constant.

If you decrease the distance between two celestial objects by a factor of 2.5, then , the new distance will become

Plug this in the above formula , we get

Hence, the force is 6.25 times stronger.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

30

step-by-step explanation:

idk

i hope i