Mathematics, 17.07.2019 19:20 JuniperGalaxy
4> solve by using laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
Answers: 2
![\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0](/tpl/images/0101/2485/a58c0.png)
![\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)](/tpl/images/0101/2485/d4ed7.png)
![\mathcal{L}[y']=s\mathcal{L}[y]-y(0)](/tpl/images/0101/2485/d8214.png)
![\mathcal{L}[x]=L](/tpl/images/0101/2485/c0c2d.png)
![\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}](/tpl/images/0101/2485/1a335.png)
![y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}](/tpl/images/0101/2485/8bb80.png)
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4> solve by using laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o...
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