3. find all solutions of the linear congruence 3x - 7y = 11 (mod 13). 4. solve each of the following sets of simultaneous congruences: (a) xel (mod 3), x = 2 (mod 5), x = 3 (mod 7). (b) x = 5 (mod 11), x = 14 (mod 29), x = 15 (mod 31). (c) = 5 (mod 6), x = 4(mod 11), r = 3 (mod 17). (d) 2x = 1 (mod 5), 3x = 9 (mod 6). 4x = 1 (mod 7), 5.x = 9 (mod 11). - 1 connee 73 med 2 3 5 b abestem

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

answer: idk

step-by-step explanation:

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10