find the arc length of the graph of the function over the indicated interval.
x = 1/3(y2 + 2)3/2, 0 ≤ y ≤ 5
find the arc length of the graph of the function over the indicated interval.
x = 1/3sqrt1a. gify(y − 3), 1 ≤ y ≤ 36

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

answer: 1 + 1 = 11

step-by-step explanation: