solve the triangle.
b = 72°, b = 12, c = 8 (1 point)

a=11.8,b=12,c=8,A=68.7°, B=72°, C= 39.3°

Step-by-step explanation:

Given data:

b = 12

c= 8

a= ?

∠B= 72°

∠C= ?

∠A=?

To find the missing angle we will use law of sine:

a/sinA=b/sinB=c/sinC

Find m∠C.

b/sinB = c/sinC

Substitute the values:

12/sin72°=8/sinC

Apply cross multiplication.

12*sinC=sin72° * 8

sinC=0.951*8/12

sinC=7.608/12

sinC= 0.634

C= 39.3°

Now we know that the sum of angles = 180°

So,

m∠A+m∠B+m∠C=180°

m∠A+72°+39.3°=180°

m∠A=180°-72°-39.3°

m∠A= 68.7°

Now find the side a:

a/sinA=b/sinB

a/sin68.7°=12/sin72°

Apply cross multiplication:

a*sin72°=12*sin68.7°

a*0.951=12*0.931

a=0.931*12/0.951

a=11.172/0.951

a=11.75

a=11.8