Then find the area s of the region.

y=2 x^2, y^2=1/2 x

Recall that the area under a curve and above the x axis can be computed by the definite integral.  If we have two curves

        y = f(x) and y = g(x)

such that 

        f(x) > g(x) 

then the area between them bounded by the horizontal lines x = a and x = b is

To remember this formula we write

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

l.ln.lln.k.nkl

step-by-step explanation: