Type the correct answer in the box. use numerals instead of words. for this problem, a non-integer answer should be entered as a fraction in simplest form using / as the fraction bar. malik randomly picked two numbers from 1 to 9 (including 1 and 9). the same number could be picked more than once. the first of the two numbers he picks is odd and less than 5. what is the probability that the sum of the two numbers malik picks is less than 5, given that the first number is odd and less than 5?

P (sum of two numbers is < 5) =2/9

Step-by-step explanation:

There are two numbers that can be picked such that the first number odd and less than 5:  1 and 3.

Then, the numbers that can be drawn with these numbers should be from: 1, 2, 3, 4, 5, 6, 7, 8 or 9.

The number of total possibilities = 18

Out of these, the following are the four possible options to have a sum which is less than 5 and 1:

1 and 1

1  and 2

1 and 3

3 and 1

So P (sum of two numbers is < 5) = = 2/9

Step-by-step explanation:

2/9 is right because i just took it and got a 5/5

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)