A(5, 3), b (2, 1), and c (-2, 4) are the coordinates of a triangle's vertices. if the triangle is reflected over the x-axis, what are the coordinates of the image?

A(5,3)  ->A'(5,-3)

B(2,1)   ->B'(2,-1)

C(-2,4)  ->C'(-2,-4)

Step-by-step explanation:

If a point is reflected over the x-axis, it ends up on the opposite side of the x-axis with the same distance from the x-axis.

So what that means is the x-coordinate will stay the same and the y-coordinate will be opposite of what it was.

So if we reflect each of your points through the x-axis you will get:

A(5,3)  ->A'(5,-3)

B(2,1)   ->B'(2,-1)

C(-2,4)  ->C'(-2,-4)

(5,-3) (2,-1) (-2,-4)

Step-by-step explanation:

When reflection over the x-axis the rule is (x,y) becomes (x, -y)

so your x will stay the same but your y will change

understand that i don't know the answers

will someone answer his question

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.