Give an example of a relation on {a, b, c} that is: 23. reflexive, symmetric, and transitive. 24. reflexive, symmetric, but not transitive. 25. reflexive, transitive, but not symmetric. 26. symmetric, transitive, but not reflexive. 27. reflexive, but neither symmetric nor transitive. 28. symmetric, but neither transitive nor reflexive. 29. transitive, but neither reflexive nor symmetric. 30. neither reflexive, symmetric, nor transitive. 31. symmetric, but not antisymmetric. 32. antisymmetric, but not symmetric. 33. symmetric and antisymmetric 34. neither symmetric nor antisymmetric. 4n on 1a h cl

step-by-step explanation:

l.ln.lln.k.nkl

step-by-step explanation:

answer: give more info

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.