Agiven line has the equation .
2x - 12y = -1
what is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?
a. y = -6x + 9
b. y = - 1/6x + 9
c. y = 1/6x +9
d. 6x+ 9

  A.  Y = -6X + 9

Step-by-step explanation:

Solving for y, we can find the slope of the given line. It is the coefficient of x, 1/6.

  -12y = -2x -1

  y = 1/6x +1/12

The perpendicular line will have a slope that is the negative reciprocal of this:

  m = -1/(1/6) = -6

The y-intercept will be the y-value corresponding to x=0. That value is b=9, given to us by the point the line is to go through. So, we have the slope-intercept form ...

  y = mx + b

  y = -6x + 9

- (2, -7)

- lines r and s and lines t and u must be parallel

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5