Ineed to answer this before 11: 59 pm by today , i will give you 10 !
an object is thrown upward at a speed of 58 feet per second by a machine from a height of 7 feet off the ground. the height h of the object after t seconds can be found using the equation h=−16t^2+58t+7
when will the height be 17 feet?
when will the object reach the ground?

For first part, t= 0.18 sec or 3.4 sec.

For second part, t= 3.7 sec.

Step by step

First part:

Set h(t) = 17and solve for tt.

-16t²+ 58t + 7= 17

-16t² + 58t - 10 = 0

Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 17 on the way up, and the higher value is the time to reach 17 again, on the way down.

Second part:

Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.

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a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you