[30 points] with volume! a circular swimming pool has a radius of 7 m and a depth of 1.4 meters. it is filled to the top with water. it develops a leak and loses 5 cubic meters of water every 2 hours. after how long would the water in the swimming pool be at a depth of 0.9 m?
use 3.14 for pi.
volume of a cylinder pi × r squared × depth.
round your answer to the nearest hours.
give an explanation with your answer! a detailed answer will get brainliest. : )

Around 31 hours

Step-by-step explanation:

So since the formula for cylinder is pi × r squared × depth, you will get 215.51 cubic meters. When it's 0.9 m, it will be 138.54.

The pool has a leak and loses 5 cubic meters every 2 hours.

Subtract 5 from 215.51 until you get 140.51 when you can no longer subtract 5.  

It will be 15 times. Which is 30 hours. Subtract 2.5 from 140.51 and you get around 138.01. Now that was an hour. 30+1= 31 hours

because they could drop even lower..

2/3=10/15

1/5=3/15

10+3=13/15

2 13/15 is the answer