According to a recent report, 66.9% of men and 50.4 % of women in the united states were overwoight, given that 48.0% of americans are men and 51 2% are women, find the probability that a randoméy selected american fits the following description. (a) an overweight man (b) overweight (e) are the events that an adut is a man and that an adult is overweight independent? explain (a) the probability that a nandomly selected adult is an overweight man is (type an integer or decimal rounded to three decimal places as needed)

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b