Which of these is an example of using financial reserves for a occasional expense? a. you know that your car will need a tune-up and other routine maintenance every winter, so you save a little money every month in preparation and use the saved money to pay when winter comes around. b. you are hit with a summer heat wave and your utility bill spikes, so you use your credit card to pay the bill and pay off the balance over the next few months. c. you graduate college and need to start paying back your student loans, so you devote some of your income every month to paying down the debt. d. you are never quite sure how much money you spend on food every month, and every so often you need to pull a tiny bit from your retirement fund to pay for groceries.

The correct answer is:

A) You know that your car will need a tune-up and other routine maintenance every winter, so you save a little money every month in preparation and use the saved money to pay when winter comes around.

Explanation:

An occasional expense is one that does not happen every month. Winter maintenance would count as occasional. Saving a little money each month to make sure you have enough to perform winter maintenance is using financial reserves for occasional expenses.

i dont know sorry

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.