Ahamburger bun merchant can ship 8 large boxes or 10 small boxes of hamburger buns into a carton for shipping. in one shipment, he sent a total of 96 boxes of hamburger buns. if there are more large boxes than small boxes, how many cartons did he ship?

11 cartons

Step-by-step explanation:

Number of large boxes that can be contained in a carton = 8

Number of small boxes that can be contained in a carton = 10

Total number of boxes sent in one shipment = 96

This shipment contains both large and small boxes. Let there be x cartons of large boxes and y cartons of small boxes in one shipment. So, we can say,

Total number of large boxes in one shipment = Number of boxes in one carton * Total number of cartons = 8x

Similarly,

Total number of small boxes in one shipment = 10y

Since, total number of boxes in one shipment is 96, we can set up the equation as:

8x + 10y = 96

This equation can have following possible solutions:

We are given in the statement that are more large boxes than the small boxes, the valid solutions are:

Assuming that he sent both large and small boxes, the only valid solution will be:

This means, the merchant sent 7 cartons of large boxes i.e. 56 large boxes and 4 cartons of small boxes i.e. 40 small boxes. So in total he sent 11 cartons.

11 boxes total   4 small    7 large  

Step-by-step explanation:

1 small box *10 = 10             96-10 = 86 (NO MULTIPLE OF 8)

2 small boxes*10=20          96-29=76 ( no multiple of 8)

3 small boxes  *10=30        96-30= 66(no multiple of 8)

4 small boxes*10 = 40        96-40 = 56 (YES multiple of 8)      56/8 = 7   (7 large boxes)

4 large boxes and 7 large boxes

so what is the question

step-by-step explanation:

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: