Write the standard form of the equation that is parallel to y = -3x + 3 and goes through point (-5, 5).

3x + y = -10. The standard form of the equation that is parallel to y = -3x + 3 and goes through point (-5, 5) is 3x + y = -10.

The equation is written in the slope-intercept form y = mx +b. So:

y = -3x + 3

The slope m = -3

Since the slopes of parallel lines are the same, we are looking for a slope line m = -3 and goes through point (-5, 5).

With the slope-intercept form:

y = mx + b

Introducing the slope m = -3:

y = -3x + b

Introducing the point (-5, 5):

5 = -3(-5) + b

5 = 15 + b

b= 5 - 15

b = -10

then

y = -3x -10

write the equation in standard form ax + by = c:

y = -3x -10

3x + y = -10

step-by-step explanation:

jjj

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400