Mathematics, 10.07.2019 04:50 dylan102247
Solve the ivp: xy' - 2xy = 10x^2, y(0) = 1 y = 3e^-2x + 2x^2 - 4 y = -3/2e^-2x + 5x + 5/2 y = 6e^2x - 5x - 5 y = 7/2e^2x - 5x - 5/2
Answers: 2
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Solve the ivp: xy' - 2xy = 10x^2, y(0) = 1 y = 3e^-2x + 2x^2 - 4 y = -3/2e^-2x + 5x + 5/2 y = 6e^2x...
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