Assume that photo coordinates (in mm) of points a and b are xa=65.35, ya=74.88 and xb=31.45, yb= -55.50. what is the photo distance ab?
(a) 134.7
(b) 39.05
(c) 162.4
(d) 92.68

Option A (134.7mm)

Step-by-step explanation:

Let's find the distance, but first we need to remember that the distance between two points with coordinates (Xa,Ya) and (Xb,Yb) is defined by:

From the situation we notice that:

Xb=31.45 and Xa=65.35, as well as:

Yb=-55.50 and Ya=74.88

Using the previous equation we have:

In conclusion, the distance between points (65.35,74.88) and (31.45,-55.50) is 134.7151mm, which is option A (134.7mm).

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step-by-step explanation:

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