Mathematics, 10.07.2019 02:30 makenziehook8

L. z and 2z have equal cardinality becausef: z 2z defined byf(n)-2n is a bijection: fis one-to-one because if f(a)-f(b), then 2a -2b which gives that a-b. fis onto because if 2ke 22, then k e z and/(k)-2k

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L. z and 2z have equal cardinality becausef: z 2z defined byf(n)-2n is a bijection: fis one-to-one...