What is the solution set of this system of equations?
y=x2-3x-4
x=y+8
a {(-1.0), (4.0)}
b. {(8.0). (0.8)}
c. {(0.0)}
d. {(2. -6)
e
there is no real solution.
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No real solutions.

Step-by-step explanation:

I'm going to subtract the second expression for y and plug it into the first equation.

So solving x=y+8 for y by subtracting 8 on both sides gives us y=x-8.

I'm going to insert this for the first y like so:

Now I'm going to move everything to one side.

I'm going to subtract x on both sides and add 8 on both sides.

Simplifying:

Now our job since the coefficient of x^2 is 1 is to find two numbers that multiply to be 4 and at the same time add up to be -3. I can't think of any such numbers.

Let's check the discriminant.

Compare to .

So .

The discriminant is .

So plugging in our numbers we get .

Time to simplify:

So since the discriminant is negative, then the solutions will not be real.

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

l.ln.lln.k.nkl

step-by-step explanation: