The first-, second-, and third-year enrollment values for a technical school are shown in the table below.

enrollment at a technical school
year (x) first year f(x) second year s(x) third year t(x)
2009 785 756 756
2010 740 785 740
2011 690 710 781
2012 732 732 710
2013 781 755 800

which of the following statements is true based on the data in the table? (2 points)

the solution to f(x) = t(x) is x = 781.
the solution to f(x) = t(x) is x = 2,011.
the solution to s(x) = t(x) is x = 756.
the solution to s(x) = t(x) is x = 2,009.

The answer should be choice C

C

Step-by-step explanation:

Did the test. Got i right

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

~

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c