Tiles spelling the word “restaurant” are placed on a sign above a building. if one of the letters falls down at random, what is the probability that the letter is not a vowel? justify

3/5

Step-by-step explanation:

The word "Restaurant" contains a total of 10 letters, out of which 4 of the letters are vowels and 6 of the letters are consonants. The probability of selecting a vowel out of this word is:

P(selected letter is a vowel) = number of vowels/number of letters.

P(selected letter is a vowel) = 4/10 = 2/5.

Similarly, probability of selecting a non-vowel out of this word is:

P(selected letter is not a vowel) = number of non-vowels/number of letters.

P(selected letter is not a vowel) = 6/10 = 3/5.

Given that one of the letters randomly falls down, and assuming that the probabilities of each letter falling down is uniform and independent from each other, then:

P(a non-vowel falls down) = non-vowels/total = 6/10 = 3/5.

So the correct answer is 3/5!!!

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)