Which shows x^2 + 2x = 3 as a perfect square equation? what are the solution(s)?
a. x^2+2x-3=0; -3 and 1
b. x^2+2x+1=0; -1
c. (x+1)^2=4; -3 and 1
d. (x+1)^2=0; -1

First we can rewrite the equation to,

Which factors to,

And this leads towards two solutions,

and,

The answer is A.

Hope this helps.

r3t40

c

Step-by-step explanation:

Given

x² + 2x = 3

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(1)x + 1 = 3 + 1

(x + 1)² = 4 ( take the square root of both sides )

x + 1 = ± = ± 2 ( subtract 1 from both sides )

x = - 1 ± 2, hence

x = - 1 - 2 = - 3 and x = - 1 + 2 = 1

answer: a.

step-by-step explanation: the answer is a. because, you need to converge the fractions to find a solution.

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb