what is the solution set of |2x + 1| > 5?
a {x|1 < x < –3}
b {x|–1 < x < 3}
c {x|x > 2 or x < –3}
d {x|x < 2 or x > –3}

Answer choice C

Step-by-step explanation:

When the values of x are greater than 2, the solution works. When the values oclf x are less than 3, the solution also works. :)

C

Step-by-step explanation:

Inequalities of the form | x | > a have solutions of the form

x < - a OR x > a, thus

2x + 1 < - 5 OR 2x + 1 > 5 ( subtract 1 from both sides of both )

2x < - 6 OR 2x > 4 ( divide both sides of both by 2)

x < - 3 OR x > 2

Solution set is

{ x | x > 2 or x < - 3 } → C

step-by-step explanation:

2x^2+5x+17

your welcome. : )