1/2[sin(2θ + 7θ) + sin(2θ - 7θ)] =
cos2θcos7θ
cos2θsin7θ
sin2θcos7θ
sin2θsi...
Mathematics, 05.07.2019 08:10 emcarrell683
1/2[sin(2θ + 7θ) + sin(2θ - 7θ)] =
cos2θcos7θ
cos2θsin7θ
sin2θcos7θ
sin2θsin7θ
Answers: 1
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