Aproduction process consists of a three-step operation. the scrap rate is 17 percent for the first step and 9 percent for the other two steps.
a. if the desired daily output is 496 units, how many units must be started to allow for loss due to scrap? (do not round intermediate calculations. round up your final answer to the next whole number.)
number of units
b. if the scrap rate for each step could be cut in half at every operation, how many units would this save in terms of the scrap allowance? (do not round intermediate calculations. round up your final answer to the next whole number.)
number of units
c. if the scrap represents a cost of $10 per unit, how much is it costing the company per day for the original scrap rate (i. e. the part a scrap rate)? (round your final answer to the nearest whole number. omit the "$" sign in your response.)
cost $

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the answer is a.

step-by-step explanation:

in three games of golf, alex shot two under par four times.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)