What are the zeros of the function f(x)=x^2+x-6 divides by x^2-x-6?

It is B.

Step-by-step explanation:

x^2+x-6 /  x^2-x-6 = 0

The numerator equates to zero:

x^2 + x - 6 = 0

(x + 3)(x - 2) = 0

the zeroes are {-3, 2).

it is contrapositive

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