Tony has $727.29 in his checking account. he must maintain a $500 balance to avoid a fee. he wrote a check for $248.50 today. write and solve an inequality to solve for the least amount of money he needs to deposit to avoid a fee.
727.29 + 248.50 − x ≥ 500; x ≥ $475.79
727.29 + 248.50 − x ≤ 500; x ≤ $475.79
727.29 − 248.50 + x ≥ 500; x ≥ $21.21
727.29 – 248.50 − x ≤ 500; x ≤ $21.21

727.29 − 248.50 + x ≥ 500; x ≥ $21.21

Step-by-step explanation:

Write down all the data given :

Beginning amount : $727.29

Balance to be maintained : $ 500

Check : $248.5

Current balance = 727.29 - 248.5 = $478.79

Tony must maintain a balance of $500 so he should have at least $21.21 more (500-478.79)

727.29 - 248.5 + 21.21 = 500

500=500

x can be 21.21 or greater than that which would maintain the balance of $500 or more.

Therefore the third statement is correct.

727.29 − 248.50 + x ≥ 500; x ≥ $21.21

!!

x+14

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