Solve the system of equations given below.
8x + 4y = 16
7y = 15
-
1
oa. (4,-2)
b. (-2,4)
c. (1.2)
:
d.
(2,1)
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x = \frac{13}{14}

Step-by-step explanation:

8x+4y=16

7y=15

the easiest unknown to find first is y because we have the second equation contains only y :

7y=15   we divide both sides by 7 we get : y=\frac{15}{7}

then we can substitute this value in the first equation to find x :

8x+4 \frac{15}{7} = 16

means : 8x+\frac{60}{7} = 16

8x=16-\frac{60}{7}

8x = \frac{52}{7}

divide both sides by 8 :

x = \frac{13}{14}

so the solution is (\frac{13}{14},\frac{15}{7})

no he doesnt because "-16' is negatiive

step-by-step explanation: