Abox contains 12 balls numbered 1 through 12. two balls are drawn in succession without replacement. if the second ball has the number 4 on it, what is the probability that the first ball had a smaller number on it? an even number on it? the probability that the first ball had a smaller number is nothing.

A box contains 12 balls numbered 1 through 12.

Also the ball are drawn without replacement.

a)

The probability that the first ball had a smaller number on it.

i.e. the number on the first ball could be: {1,2,3}

Hence, the probability  that the first ball had a smaller number on it is:

b)

The probability that the first ball has a even number on it is:

There are total 6 even numbers {2,4,6,8,10,12}

but 4 can't be considered as it comes on the second draw, so we are left with just 5 balls with even number.

Hence, the probability is:

10 glasses of juice could be made with 5 carrots, 1,500 orange juice, 2,000 papaya juice.

14.3

step-by-step explanation:

add all the numbers together.

9 + 12 + 15 + 16 + 17 + 17 = 86

now, divide 86 by how many numbers we have: 6.

86 / 6 = 14.3