15) if mzbfc = (8x - 4)º, find x.
Mathematics, 01.07.2019 15:10 danielhall
use rhombus abcd and the given information to solve #15-18.
15) if mzbfc = (8x - 4)º, find x.
16) if mzbaf = 31°, find mzbca.
17) if ab = 7x - 12 and bc = 8x - 22, find ad.
18) if mzadb =(x- 15)° and mzcdb = (2x), find the value(s) of x.
Answers: 1
Mathematics, 21.06.2019 18:00, madiballet125
What are the equivalent ratios for 24/2= /3= /5.5=108/ = /15
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Mathematics, 21.06.2019 18:50, BrainzOli7408
If sr is 4.5cm and tr is 3cm, what is the measure in degrees of angle s?
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Mathematics, 21.06.2019 21:30, chrisgramjooooo2366
In δabc shown below, ∠bac is congruent to ∠bca: triangle abc, where angles a and c are congruent given: base ∠bac and ∠acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: m∠bda and m∠bdc is 90° by the definition of a perpendicular bisector. ∠bda is congruent to ∠bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
use rhombus abcd and the given information to solve #15-18.
15) if mzbfc = (8x - 4)º, find x.
15) if mzbfc = (8x - 4)º, find x.
Mathematics, 24.06.2019 07:30
English, 24.06.2019 07:30
Mathematics, 24.06.2019 07:30