Below is a list of 30 students numbered from 00 to 29. use the random number table below to put exactly 6 of these students into a treatment group. start with the first line of the table (line 101). list the students of the treatment group in the order in which their numbers come up in the table.
00 aaron
01 buffy
02 chandler
03 cindy
04 drusilla
05 eric
06 fallon
07 graham
08 heather
09 hsin0chi
10 ismail
11 jasmine
12 kiefer
13 lucia
14 monte
15 naomi
16 otis
17 polly
18 quincy
19 rachael
20 sarah
21 stacy
22 tasha
23 turan
24 ukiah
25 valerie
26 wahib
27 xandra
28 yale
29 zach
part a: search through the list of pairs that match student numbers and circle each one found. if a student number is repeated, only use the first occurrence. stop when you have 6 matches.
part b: list the 6 matching student numbers you found.
part c: which 6 students will be in the treatment group?

nope.   happens to me as well.

-aparri

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.