Mathematics, 29.06.2019 08:10 simoncastro1
The average value of the function f (t) =(t-4)^2 on [0,9] is
Answers: 1
![\frac{1}{9-0} [\frac{(9-4)^3}{3}-\frac{(0-4)^3}{3}]](/tpl/images/0030/3137/c028f.png)
![\frac{1}{9} [\frac{5^3}{3}-\frac{(-4)^3}{3}]](/tpl/images/0030/3137/b6d5c.png)
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