Suppose that you need to create a list of n values that have a specific known mean. some of the n values can be freely selected. how many of the n values can be freely assigned before the remaining values are determined

  n-1

Step-by-step explanation:

All but one of the values may be freely chosen. The last one must be chosen to bring the sum to the a value that is n times the mean.

a maximum of n-1 can be freely selected

Step-by-step explanation:

The fact that we already know the mean means that, if we have n values:

X = (x₁ + x₂ + + xₙ)/n

where X is known and n is known.

Now, suppose we can assign n freely therms: this is not the case, because if X is different than 0, we could assign the n values equal to zero and the equality would be false.

Now suppose we can assign n-1 values freely, then we would have the equation:

X = (x₁ + x₂ +)/n + xₙ/n

where the term (x₁ + x₂ + ..) is conformed with the random values and xₙ must be chosen in order to satisfy the equation. So we would have the equation:

(X -  (x₁ + x₂ +)/n)*n = n*X -  (x₁ + x₂ +) = xₙ  

The equation that can be solved, so a maximum of n-1 can be freely selected.

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all