Pretend you're playing a carnival game and you've won the lottery, sort of. you have the opportunity to select five bills from a money bag, while blindfolded. the bill values are $1, $2, $5, $10, $20, $50, and $100. how many different possible ways can you choose the five bills? (order doesn't matter, and there are at least five of each type of bill.)

The total number of ways are:

                       462

When we are asked to select r items from a set of n items that the rule that is used to solve the problem is:

Method of combination.

Here the total number of bills of different values are: 7

i.e. n=7

(  $1, $2, $5, $10, $20, $50, and $100 )

and there are atleast five of each type of bill.

Also, we have to choose 5 bills i.e. r=5

The repetition is  allowed while choosing bills.

Hence, the formula is given by:

Hence, we get:

           Hence, the answer is:

                  462

marco saved more.   he saved $35 more.

step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

3201

step-by-step explanation: